Housie random number generator

1. Lowest number is 1 and highest number is 90
2. Numbers already called are to be displayed
3. Just previous number of Call is to be displayed
4. One time use random ( sequence ) numbers

Generating Numbers

list1=random.sample(range(1,91), 90) 
my_iter=iter(list1) # creating iterator

Displaying grid of numbers

def display_no(): # display all buttons at starting
    row=3
    col=2
    for i in range(1,91):
        btn = tk.Button(my_w, text=i,font=font2,
         bg='#ffffff',fg='#C0c0c0')
        btn.grid(row=row, column=col,padx=2)
        if(col==11):  # one row is complete, move next 
            col=2     # staring column 
            row=row+1 # next row 
        else:
            col=col+1 # move to next column ( same row ) 
        buttons.append(btn) # keep the button reference 

Call for Number

def my_next(): # Click of Next button 
    global s_no2
    #print(s_no2)
    str2.set(str(s_no2)) # set the previous call number
    try:
        s_no=next(my_iter) # Get the call number 
        buttons[s_no-1].config(bg="lightgreen",fg='#000000')
        str1.set(str(s_no))
        s_no2=s_no  # store to use as previous call number 
    except StopIteration: # No more number available
        str1.set('0')
        print ("This is a StopIteration error")

import random
list1=random.sample(range(1,91), 90) 
my_iter=iter(list1) # creating iterator
import tkinter as tk
my_w = tk.Tk()
my_w.geometry("410x500")  # Size of the window 
my_w.title('www.plus2net.com')

font1=('times', 64, 'bold')  # font style of Last call 
font2=('times', 14, 'normal') # font style of grid numbers
font3=('times', 20, 'bold')  # font style of the button

b1=tk.Button(my_w,text='Next',font=font3,command=lambda:my_next())
b1.grid(row=1,column=1,columnspan=5) # show the button to click

str1=tk.StringVar() # Last call to display 
str2=tk.StringVar() # Previous to Last call 
str1.set(0)  # Initial value
str2.set(0)  # Initial value
l1=tk.Label(my_w,textvariable=str1,font=font1) # Show the call
l1.grid(row=1,column=5,columnspan=3,padx=10) 
l2=tk.Label(my_w,textvariable=str2) # show previous to call
l2.grid(row=1,column=9,padx=10)

buttons=[] # to store reference to buttons

def display_no(): # display all buttons at starting
    row=3
    col=2
    for i in range(1,91):
        btn = tk.Button(my_w, text=i,font=font2,
         bg='#ffffff',fg='#C0c0c0')
        btn.grid(row=row, column=col,padx=2)
        if(col==11):  # one row is complete, move next 
            col=2     # staring column 
            row=row+1 # next row 
        else:
            col=col+1 # move to next column ( same row ) 
        buttons.append(btn) # keep the button reference 
global s_no2
s_no2=0

def my_next(): # Click of Next button 
    global s_no2
    #print(s_no2)
    str2.set(str(s_no2)) # set the previous call number
    try:
        s_no=next(my_iter) # Get the call number
        buttons[s_no-1].config(bg="lightgreen",fg='#000000')
        str1.set(str(s_no)) 
        s_no2=s_no # store to use as previous call number
    except StopIteration: # No more number available
        str1.set('0')
        print ("This is a StopIteration error")
    
display_no() # show all the numbers in layout

copyright_symbol = u"\u00A9"
l1_end=tk.Label(my_w,text=copyright_symbol) # footer messages
l1_end.grid(row=14,column=1,padx=4)
l2_end=tk.Label(my_w,text='www.plus2net.com') #footer
l2_end.grid(row=14,column=2,columnspan=5,padx=20,pady=10)

my_w.mainloop()  # Keep the window open

Subhendu Mohapatra

Author & Instructor at plus2net

I write and maintain practical tutorials on Python, PHP, SQL, JavaScript, HTML, jQuery, and web development at plus2net. The tutorials focus on clear explanations, working examples, and code that readers can test and adapt while learning.

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