
import tkinter as tk
from tkinter import ttk,filedialog
from tkinter.filedialog import askopenfile
my_w = tk.Tk()
my_w.geometry("400x300") # Size of the window
my_w.title('www.plus2net.com')
my_font1=('times', 18, 'bold')
l1 = tk.Label(my_w,text='Upload File & read',width=30,font=my_font1)
l1.grid(row=1,column=1)
b1 = tk.Button(my_w, text='Upload File',
width=20,command = lambda:upload_file())
b1.grid(row=2,column=1)
trv=ttk.Treeview(my_w,selectmode='browse')
trv.grid(row=3,column=1,columnspan=4,padx=20,pady=20)
trv['show'] = 'tree'
def upload_file():
file = filedialog.askopenfilename(
filetypes=[("CSV files", ".csv")])
if file:
fob=open(file,'r')
i=0
for data in fob:
trv.insert("",'end',iid=i,text=data)
i=i+1
else:
print("No file chosen")
my_w.mainloop() # Keep the window open
if file: in above code. The else part of the code will display the message. Author & Instructor at plus2net
I write and maintain practical tutorials on Python, PHP, SQL, JavaScript, HTML, jQuery, and web development at plus2net. The tutorials focus on clear explanations, working examples, and code that readers can test and adapt while learning.