Python set isdisjoint(): Check for No Common Elements

A.isdisjoint(other) returns True when A and the other iterable have no elements in common. If they share at least one element, it returns False.

This is closely related to intersection(): two sets are disjoint when their intersection is empty. Compare it with issubset() and issuperset().

Set order: sets are unordered. Whenever an example prints a set, the displayed element order can differ between runs or Python environments.

A={'x','y','z'}
B={'x','b','c'}
print(A.isdisjoint(B))

Output ( 'x' is the common element among two sets A and B )

False

A={'x','y','z'}
B={'a','b','c'}
print(A.isdisjoint(B))

Output ( There is no common element among two sets A and B )

True

Using a String

String is an iterable objects

A={'x','y','z'}
B='Alex'
print(A.isdisjoint(B))

Output ( here x is the common element )

False

Using a List

List is an iterable objects

A={'x','y','z'}
B=['a','b','c']
print(A.isdisjoint(B))

Output (No common elements )

True

All Set Methods Subset / Superset / Disjoint Questions with solutions on set issubset() issuperset()

tuple set Dictionary Python- Tutorials

Subhendu Mohapatra

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Python set isdisjoint() Method

Using a String

Using a List

Subhendu Mohapatra