isdisjoint() method checks and returns True or False based on common element among them

isdisjoint(set) takes one set ( any iterable ) as argument .

set : set to checked
While checking we can use iterable objects like string , list etc Returns : True or False
isdisjoint False

A={'x','y','z'}
B={'x','b','c'}
print(A.isdisjoint(B))

Output ( 'x' is the common element among two sets A and B )

False

A={'x','y','z'}
B={'a','b','c'}
print(A.isdisjoint(B))

Output ( There is no common element among two sets A and B )

True

Using stirng

String is an iterable objects

A={'x','y','z'}
B='Alex'
print(A.isdisjoint(B))

Outut ( here x is the common element )

False

Using list

List is an iterable objects

A={'x','y','z'}
B=['a','b','c']
print(A.isdisjoint(B))

Output (No common elements )

True

All set methods Questions with solutions on set issubset() issuperset()

tuple set Dictionary Python- Tutorials

Subhendu Mohapatra

Author & Instructor at plus2net

I write and maintain practical tutorials on Python, PHP, SQL, JavaScript, HTML, jQuery, and web development at plus2net. The tutorials focus on clear explanations, working examples, and code that readers can test and adapt while learning.

About the author Watch on YouTube

Connect:

Subscribe to our YouTube Channel here

isdisjoint() method for set

Using stirng

Using list

Subhendu Mohapatra